0=2x^2+36x-9

Solution for 0=2x^2+36x-9 equation:

0=2x^2+36x-9

We move all terms to the left:

0-(2x^2+36x-9)=0

We add all the numbers together, and all the variables

-(2x^2+36x-9)=0

We get rid of parentheses

-2x^2-36x+9=0

a = -2; b = -36; c = +9;
Δ = b2-4ac
Δ = -362-4·(-2)·9
Δ = 1368
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1368}=\sqrt{36*38}=\sqrt{36}*\sqrt{38}=6\sqrt{38}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-6\sqrt{38}}{2*-2}=\frac{36-6\sqrt{38}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+6\sqrt{38}}{2*-2}=\frac{36+6\sqrt{38}}{-4}
$